Machine Design According to I.B.R., when the thickness of boiler shell (t) is greater than 8 mm, then the diameter of rivet hole (d) is obtained by Equating tearing resistance of the plate to the shearing resistance of the rivets Equating shearing resistance to the crushing resistance of the rivets Equating tearing resistance of the plate to the crushing resistance of the rivets None of these Equating tearing resistance of the plate to the shearing resistance of the rivets Equating shearing resistance to the crushing resistance of the rivets Equating tearing resistance of the plate to the crushing resistance of the rivets None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design The lower deviation is the algebraic difference between the Actual size and the corresponding basic size Maximum limit and the basic size Minimum limit and the basic size None of these Actual size and the corresponding basic size Maximum limit and the basic size Minimum limit and the basic size None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design A connecting rod subjected to an axial load may buckle with X-axis as neutral axis Y-axis as neutral axis Z-axis X-axis or Y-axis as neutral axis X-axis as neutral axis Y-axis as neutral axis Z-axis X-axis or Y-axis as neutral axis ANSWER DOWNLOAD EXAMIANS APP
Machine Design A bolt of M 24 × 2 means that The nominal diameter of bolt is 24 mm and pitch is 2 mm The pitch of the thread is 24 mm and depth is 2 mm The effective diameter of bolt is 24 mm and there are 2 threads per cm Cross-sectional area of the threads is 24 mm² The nominal diameter of bolt is 24 mm and pitch is 2 mm The pitch of the thread is 24 mm and depth is 2 mm The effective diameter of bolt is 24 mm and there are 2 threads per cm Cross-sectional area of the threads is 24 mm² ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension) ⅟₂× (P1 + P2) [(√P1 + √P2)/2]² P1 + P2 [⅟₂ × (P1 + P2)] + Pc ⅟₂× (P1 + P2) [(√P1 + √P2)/2]² P1 + P2 [⅟₂ × (P1 + P2)] + Pc ANSWER DOWNLOAD EXAMIANS APP
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