Machine Design An elastic bar is fixed at the upper end and loaded at the lower end by a falling weight. The shock load produced can be reduced by Decreasing the modulus of elasticity of the bar Increasing the length of bar Decreasing the cross-sectional area of the bar All of these Decreasing the modulus of elasticity of the bar Increasing the length of bar Decreasing the cross-sectional area of the bar All of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design The endurance or fatigue limit is defined as the maximum value of the stress which a polished standard specimen can withstand without failure, for infinite number of cycles, when subjected to Completely reversed load Static load Dynamic load Static as well as dynamic load Completely reversed load Static load Dynamic load Static as well as dynamic load ANSWER DOWNLOAD EXAMIANS APP
Machine Design A feather key is generally Tight in both shaft and hub Loose in both shaft and hub Loose in shaft and tight in hub Tight in shaft and loose in hub Tight in both shaft and hub Loose in both shaft and hub Loose in shaft and tight in hub Tight in shaft and loose in hub ANSWER DOWNLOAD EXAMIANS APP
Machine Design The bearing characteristic number in a hydrodynamic bearing depends upon Length, width and load Viscosity, speed and bearing pressure Viscosity, speed and load Length, width and speed Length, width and load Viscosity, speed and bearing pressure Viscosity, speed and load Length, width and speed ANSWER DOWNLOAD EXAMIANS APP
Machine Design The application of second type levers is found in Handle of a hand pump Hand wheel of a punching press Lever of a loaded safety valve A pair of tongs Handle of a hand pump Hand wheel of a punching press Lever of a loaded safety valve A pair of tongs ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα ANSWER DOWNLOAD EXAMIANS APP
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