SSC JE Electrical 2019 with solution SET-1 In the speed-time curve of a train, speed in and time are plotted km/h; sec km/h; hour km/s; sec km/s; hour km/h; sec km/h; hour km/s; sec km/s; hour ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 Extension of moving iron ammeter range can be done by using Multiplier Inductor Capacitor Shunt Multiplier Inductor Capacitor Shunt ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 A single-phase circuit’s power factor can be measured with a/an Combination of a voltmeter and ammeter Combination of a voltmeter, ammeter, and wattmeter Wattmeter alone Energy meter alone Combination of a voltmeter and ammeter Combination of a voltmeter, ammeter, and wattmeter Wattmeter alone Energy meter alone ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 The cheap and temporary system of the internal wiring is? Cleat wiring Conduit wiring Casing-capping CTS or TRS wiring Cleat wiring Conduit wiring Casing-capping CTS or TRS wiring ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 In an AC network, the load connected is (10 + j10). The phase relation between the voltage applied and the current through the load is: Voltage leads current by 45° Voltage lags current by 45° Voltage lags current by 30° Voltage and current are in phase with each other Voltage leads current by 45° Voltage lags current by 45° Voltage lags current by 30° Voltage and current are in phase with each other ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L0ad impedance Z = R + jXz = 10 + 10jPhase angle θ= tan−1(IL/IR)θ= tan−1(10/10)tanθ = 1tanθ =45°
SSC JE Electrical 2019 with solution SET-1 A coil is wound with 50 turns and a current 8A produces a flux of 200μWb. Calculate the inductance of the coil 0.25 mH 1.25 mH 2.5 mH 0.125 mH 0.25 mH 1.25 mH 2.5 mH 0.125 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The inductance of the coil is given by the relationL = Nφ/IWhereN = number of turns = 50φ = flux = 200μWbI = current = 8 AL = 50 × 200 × 10−6 ⁄ 8L = 1.25 mH
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