SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
4F2D is a/an number

Binary

Hexadecimal

Octal

Decimal

Binary

Hexadecimal

Octal

Decimal

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SSC JE Electrical 2019 with solution SET-1
Two inductors of 4H and 6H are connected in series. The equivalent inductance of this combination is

10 H

4 H

2.4 H

6 H

10 H

4 H

2.4 H

6 H

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SSC JE Electrical 2019 with solution SET-1
When the only current source is active in the circuit, find the current through the 10Ω resistor

1.33 A

1.66 A

0.66 A

0 A

1.33 A

1.66 A

0.66 A

0 A

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SSC JE Electrical 2019 with solution SET-1
Reflected Light/Incident Light =

Reflection factor

Waste light factor

Absorption factor

Maintenance factor

Reflection factor

Waste light factor

Absorption factor

Maintenance factor

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SSC JE Electrical 2019 with solution SET-1
A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

−2.5 V

−10 V

−4 V

0.4 V

−2.5 V

−10 V

−4 V

0.4 V

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SSC JE Electrical 2019 with solution SET-1
The average value of a sinusoidal wave is:

0.5 × maximum value

2 × maximum value

√2 × maximum value

0.637 × maximum value

0.5 × maximum value

2 × maximum value

√2 × maximum value

0.637 × maximum value

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