Internal Combustion Engines In petrol engine, using a fixed octane rating fuel and fixed compression ratio, supercharging will _________ the knocking tendency. Not effected None of these Increase Decrease Not effected None of these Increase Decrease ANSWER DOWNLOAD EXAMIANS APP
Internal Combustion Engines Iso-octane (C₈H₁₈) has octane number of 0 50 100 120 0 50 100 120 ANSWER DOWNLOAD EXAMIANS APP
Internal Combustion Engines In a typical medium speed, 4-stroke cycle diesel engine May start and end anywhere Fuel injection starts at just before top dead center and ends just after top dead center Fuel injection starts at 10° before top dead center and ends at 20° after top dead center Fuel injection starts at top dead center and ends at 20° after top dead center May start and end anywhere Fuel injection starts at just before top dead center and ends just after top dead center Fuel injection starts at 10° before top dead center and ends at 20° after top dead center Fuel injection starts at top dead center and ends at 20° after top dead center ANSWER DOWNLOAD EXAMIANS APP
Internal Combustion Engines All heat engines utilize Calorific value of fuel Low heat value of oil Net calorific value of oil High heat value of oil Calorific value of fuel Low heat value of oil Net calorific value of oil High heat value of oil ANSWER DOWNLOAD EXAMIANS APP
Internal Combustion Engines The accumulation of carbon in a cylinder results in increase of Volumetric efficiency Ignition time Effective compression ratio Clearance volume Volumetric efficiency Ignition time Effective compression ratio Clearance volume ANSWER DOWNLOAD EXAMIANS APP
Internal Combustion Engines The brake power (B.P.) of the engine is given by (where W = Brake load or dead load in newtons, l = Length of arm in meters, N = Speed of engine in r.p.m., S = Spring balance reading in newtons, D = Dia. of brake drum in meters, and d = Dia. of rope in meters) P = [(W - S) π (D + d) N]/60 watts P = [(W - S) πDN]/60 watts All of these P = (Wl × 2πN)/60 watts P = [(W - S) π (D + d) N]/60 watts P = [(W - S) πDN]/60 watts All of these P = (Wl × 2πN)/60 watts ANSWER DOWNLOAD EXAMIANS APP
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