Theory of Machine In order to give the primary balance of the reciprocating parts of a multi-cylinder inline engines The algebraic sum of the couples about any point in the plane of the primary forces must be equal to zero None of these The algebraic sum of the primary forces must be equal to zero Both (A) and (B) The algebraic sum of the couples about any point in the plane of the primary forces must be equal to zero None of these The algebraic sum of the primary forces must be equal to zero Both (A) and (B) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A rotor which is balanced statically but not dynamically is supported on two bearings L apart and at high speed of the rotor, reaction on the left bearing is R. The right side of the bearing is shifted to a new position 2L apart from the left bearing. At the same rotor speed, dynamic reaction on the left bearing in the new arrangement will Become equal to 2R Become equal to R/2 Remain same as before Become equal to R/4 Become equal to 2R Become equal to R/2 Remain same as before Become equal to R/4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The critical speed of a shaft in revolution per second is __________ as that of natural frequency of transverse vibration. Unpredictable Same Different None of these Unpredictable Same Different None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a Hartnell governor, the lift of the sleeve is given by (where r₁ and r₂ = Max. and min. radii of rotation, x = Length of ball arm of the lever, and y = Length of sleeve arm of the lever) (r₁ - r₂) (x/y) (r₁ + r₂) (y/x) (r₁ - r₂) (y/x) (r₁ + r₂) (x/y) (r₁ - r₂) (x/y) (r₁ + r₂) (y/x) (r₁ - r₂) (y/x) (r₁ + r₂) (x/y) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The motion of a shaft in a circular hole is an example of Successfully constrained motion Incompletely constrained motion Completely constrained motion None of these Successfully constrained motion Incompletely constrained motion Completely constrained motion None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a cam drive with uniform velocity follower, the sharp corners of the displacement diagram are rounded off at the beginning and at the end of each stroke. This is done Because the uniform velocity motion is a partial parabolic motion Because of difficulty in manufacturing cam profile Because of loose contact of follower with cam surface In order to have acceleration in beginning and retardation at the end of stroke within the finite limits Because the uniform velocity motion is a partial parabolic motion Because of difficulty in manufacturing cam profile Because of loose contact of follower with cam surface In order to have acceleration in beginning and retardation at the end of stroke within the finite limits ANSWER DOWNLOAD EXAMIANS APP
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