Theory of Machine The example of successfully constrained motion is a Motion of an I.C. engine valve All of these Motion of the shaft between a footstep bearing Piston reciprocating inside an engine cylinder Motion of an I.C. engine valve All of these Motion of the shaft between a footstep bearing Piston reciprocating inside an engine cylinder ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ (l₁ + l₂ + l₃)/3 l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ (l₁ + l₂ + l₃)/3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Coriolis component acts Perpendicular to sliding surfaces None of these Somewhere in between above two Along sliding surfaces Perpendicular to sliding surfaces None of these Somewhere in between above two Along sliding surfaces ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a truncated conical pivot bearing, considering uniform wear, is (2/3). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2). μ W cosec α (r₁ + r₂) (1/2). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3).μ W cosec α (r₁ + r₂) (2/3). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2). μ W cosec α (r₁ + r₂) (1/2). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3).μ W cosec α (r₁ + r₂) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A ball and a socket forms a Rolling pair Screw pair Turning pair Spherical pair Rolling pair Screw pair Turning pair Spherical pair ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine For an isochronous Hartnell governor (where r₁ and r₂ = Maximum and minimum radius of rotation of balls respectively, S₁ and S₂ = Maximum and minimum force exerted on the sleeve respectively, and M = Mass on the sleeve) (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ S₁/S₂ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ S₁/S₂ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS