Theory of Machine The example of successfully constrained motion is a Piston reciprocating inside an engine cylinder Motion of the shaft between a footstep bearing Motion of an I.C. engine valve All of these Piston reciprocating inside an engine cylinder Motion of the shaft between a footstep bearing Motion of an I.C. engine valve All of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the belt is stationary, it is subjected to some tension known as initial tension. The value of this tension is equal to the Tension in the slack side of the belt Average tension of the tight side and slack side of the belt Tension in the tight side of the belt Sum of the tensions on the tight side and slack side of the belt Tension in the slack side of the belt Average tension of the tight side and slack side of the belt Tension in the tight side of the belt Sum of the tensions on the tight side and slack side of the belt ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two pulleys of radii r₁ and r₂ and at distance x apart are connected by means of a cross belt drive. The length of the belt is π (r₁ - r₂) + [(r₁ + r₂)²/x] + 2x π (r₁ + r₂) + [(r₁ - r₂)²/x] + 2x π (r₁ + r₂) + [(r₁ + r₂)²/x] + 2x π (r₁ - r₂) + [(r₁ - r₂)²/x] + 2x π (r₁ - r₂) + [(r₁ + r₂)²/x] + 2x π (r₁ + r₂) + [(r₁ - r₂)²/x] + 2x π (r₁ + r₂) + [(r₁ + r₂)²/x] + 2x π (r₁ - r₂) + [(r₁ - r₂)²/x] + 2x ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the crank is at the outer dead centre, in a reciprocating steam engine, then the acceleration of the piston will be ω² r {(n - 1)/n} ω² r {n/(n - 1)} ω² r {(n + 1)/n} ω² r {n/(n + 1)} ω² r {(n - 1)/n} ω² r {n/(n - 1)} ω² r {(n + 1)/n} ω² r {n/(n + 1)} ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the primary direct crank of a reciprocating engine makes an angle of 'θ' with the line of stroke, then the secondary direct crank will make an angle of _________ with the line of stroke. θ/2 θ 2θ 4θ θ/2 θ 2θ 4θ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity ω₁ rad/s in the clockwise direction and the link OB turns with angular velocity ω₂ rad/s in the anticlockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O) (ω₁ - ω₂) r (ω₁ - ω₂) 2r ω₁.ω₂.r (ω₁ + ω₂) r (ω₁ - ω₂) r (ω₁ - ω₂) 2r ω₁.ω₂.r (ω₁ + ω₂) r ANSWER DOWNLOAD EXAMIANS APP
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