In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?

Problems on H.C.F and L.C.M
In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?

800,500

820,369

700,400

820,360

800,500

820,369

700,400

820,360

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Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

48

1305

875

435

48

1305

875

435

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Problems on H.C.F and L.C.M
The product of two numbers is 1320 and their H.C.F. is 6. the L.C.M. of the numbers is:

220

1326

1314

7920

220

1326

1314

7920

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Problems on H.C.F and L.C.M
If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:

55/601

11/120

601/55

120/11

55/601

11/120

601/55

120/11

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Problems on H.C.F and L.C.M
The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change

10:13:17 hrs

9:22:08 hrs

7:25:14 hrs

8:27:12 hrs

10:13:17 hrs

9:22:08 hrs

7:25:14 hrs

8:27:12 hrs

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers.

8 and 10

6 and 4

2 and 4

8 and 6

8 and 10

6 and 4

2 and 4

8 and 6

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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?

Problems on H.C.F and L.C.M LCM of 87 and 145 is:

Problems on H.C.F and L.C.M The product of two numbers is 1320 and their H.C.F. is 6. the L.C.M. of the numbers is:

Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:

Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change

Problems on H.C.F and L.C.M The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers.

Problems on H.C.F and L.C.M
In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are?

Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

Problems on H.C.F and L.C.M
The product of two numbers is 1320 and their H.C.F. is 6. the L.C.M. of the numbers is:

Problems on H.C.F and L.C.M
If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to:

Problems on H.C.F and L.C.M
The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change

Problems on H.C.F and L.C.M
The product of the L.C.M. and H.C.F. of two numbers is 24. The difference of two numbers is 2. Find the numbers.