Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 820,369 700,400 820,360 800,500 820,369 700,400 820,360 800,500 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M Find the smallest number which when increased by 5, divisible by 6, 9, 15, 20 and 24? 377 366 355 344 377 366 355 344 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A heap of stones can be made up into groups of 21. When made up into groups of 16, 20, 25 and 45 there are 3 stones left in each case. How many stones at least can there be in the heap? 4803 2403 3603 7203 4803 2403 3603 7203 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A man was employed on the promise that he will be paid the highest wages per day. The contract money to be paid was Rs. 1189. Finally he was paid only Rs. 1073. For how many days did he actually work? 40 37 39 35 40 37 39 35 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively. 445 221 127 379 445 221 127 379 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (1657 - 6) and (2037 - 5) = H.C.F. of 1651 and 2032 _______1651 ) 2032 ( 1 1651 1651_______ 381 ) 1651 ( 4 1524_________ 127 ) 381 ( 3 381 0Required number = 127.