Problems on H.C.F and L.C.M In finding the HCF of two numbers, the last divisor was 41 and the successive quotients, starting from the first, where 2, 4 and 2. The numbers are? 820,360 700,400 800,500 820,369 820,360 700,400 800,500 820,369 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: 15120 11115 15210 15110 15120 11115 15210 15110 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the least number of six digits, which when divided by 4, 6, 10 and 15, leaves in each case the same remainder of 2, be N. The sum of the digits in N is: 6 3 5 4 6 3 5 4 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest possible length which can be used to measure exactly the length 7 m, 3 m 85 cm, 12 m 95 cm is : 25 cm 35 cm 15 cm 42 cm 25 cm 35 cm 15 cm 42 cm ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 31/45 17/29 11/13 23/37 31/45 17/29 11/13 23/37 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? 66 264 132 36 66 264 132 36 ANSWER DOWNLOAD EXAMIANS APP
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