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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Find the greatest number which will divide 25, 73 and 97 as so to leave the same remainder in each case?

12
18
32
24

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

123
116
121
112

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
There are four prime numbers written in ascending order of magnitude. The product of the first three is 385 and of the last three is 1001. Find the fourth number?

13
5
11
7

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which when divided by 8, 12 and 16, leave in each remainder 3, is?

71
69
70
51

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is :

23
13
33
3

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the smallest number of five digits exactly divisible by 16,24,36 and 54.

10368
10268
10568
10468

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Smallest number of five digits is 10000.       Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432,       On dividing 10000 by 432,we get 64 as remainder.    Required number = 10000 +( 432 – 64 ) = 10368.

MORE MCQ ON Problems on H.C.F and L.C.M

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