Theory of Machine In a turning moment diagram, the variations of energy above and below the mean resisting torque line is called None of the listed here Coefficient of fluctuation of energy Maximum fluctuation of energy Fluctuation of energy None of the listed here Coefficient of fluctuation of energy Maximum fluctuation of energy Fluctuation of energy ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The primary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r (cos 2θ/n) m.ω².r cosθ m.ω².r (sin 2θ/n) m.ω².r sinθ m.ω².r (cos 2θ/n) m.ω².r cosθ m.ω².r (sin 2θ/n) m.ω².r sinθ ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The relation between number of links (l) and number of joints (j) in a kinematic chain is l = (3/4).(j + 3) l = (1/2).(j + 2) l = (2/3).(j + 2) l = j + 4 l = (3/4).(j + 3) l = (1/2).(j + 2) l = (2/3).(j + 2) l = j + 4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two heavy rotating masses are connected by shafts of lengths l₁, l₂ and l₃ and the corresponding diameters are d₁, d₂ and d₃. This system is reduced to a torsionally equivalent system having uniform diameter d = d₁ of the shaft. The equivalent length of the shaft is l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ (l₁ + l₂ + l₃)/3 l₁ + l₂ + l₃ l = l₁ + l₂.(d₁/d₂)³ + l₂.(d₁/d₃)³ l = l₁ + l₂.(d₁/d₂)⁴ + l₃.(d₁/d₃)⁴ (l₁ + l₂ + l₃)/3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The equation of motion for a single degree of freedom system with viscous damping is 4(dx²/dt²) + 9(dx/dt) + 16x. The damping ratio of the system is 44090 44082 9/128 30195 44090 44082 9/128 30195 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a truncated conical pivot bearing, considering uniform pressure, is (1/2). μ W cosecα (r₁ + r₂) (2/3). μ W cosecα (r₁ + r₂) (2/3). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2). μ W cosecα (r₁ + r₂) (2/3). μ W cosecα (r₁ + r₂) (2/3). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2). μ W cosecα [(r₁³ - r₂³)/(r₁² - r₂²)] ANSWER DOWNLOAD EXAMIANS APP