In a series RLC circuit, the supply voltage is 230 V at 50 Hz. The resonant current is 2 A at the resonant frequency of 50 Hz. Under the resonant condition, the voltage across the capacitor is measured to be equal to 460 V. What are the values of L and C?

• A. 0.73 H and 13.85 pF
• B. 0.53 H and 15.83 pF
• C. 0.53 mH and 15.83 pF
• D. 0.73 mH and 13.85 pF

Answer: (A)

Vc = I*Xc
460 = 2*(1/(2*ᴨ*50*C))
C = 2/(460*2*50*ᴨ)
= 1.385*10⁻⁵ F
= 13.85 F

V_L = I*X_L
L = V/(I*2*ᴨ*f)
= 460/(2*ᴨ*50*2)
= 0.7345 H