Theory of Machine In a locomotive, the maximum magnitude of the unbalanced force along the perpendicular to the line of stroke, is known as None of these Tractive force Hammer blow Swaying couple None of these Tractive force Hammer blow Swaying couple ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Pulley in a belt drive acts as Turning pair Cylindrical pair Rolling pair Sliding pair Turning pair Cylindrical pair Rolling pair Sliding pair ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the pitching of a ship is __________ the effect of gyroscopic couple acting on it will be to move the ship towards port side. Backward Downward Forward Upward Backward Downward Forward Upward ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A watt's governor can work satisfactorily at speeds from 200 to 300 r.p.m. 100 to 200 r.p.m. 80 to 100 r.p.m. 60 to 80 r.p.m. 200 to 300 r.p.m. 100 to 200 r.p.m. 80 to 100 r.p.m. 60 to 80 r.p.m. ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the crank is at the inner dead center, in a reciprocating steam engine, then the acceleration of the piston will be ω²r. (n - 1)/n ω²r. n/(n - 1) ω²r. n/(n + 1) ω²r. (n + 1)/n ω²r. (n - 1)/n ω²r. n/(n - 1) ω²r. n/(n + 1) ω²r. (n + 1)/n ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine For an isochronous Hartnell governor (where r₁ and r₂ = Maximum and minimum radius of rotation of balls respectively, S₁ and S₂ = Maximum and minimum force exerted on the sleeve respectively, and M = Mass on the sleeve) S₁/S₂ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ S₁/S₂ = r₁/r₂ (m.g - S₁)/(m.g - S₂) = r₂/r₁ (m.g + S₁)/(m.g + S₂) = r₁/r₂ S₂/S₁ = r₁/r₂ ANSWER DOWNLOAD EXAMIANS APP
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