RCC Structures Design In a combined footing if shear stress exceeds 5 kg/cm², the nominal stirrups provided are: 10 legged 12 legged 8 legged 6 legged 10 legged 12 legged 8 legged 6 legged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the sides of a slab simply supported on edges and spanning in two directions are equal, the maximum bending moment is multiplied by 0.4 0.5 0.7 0.6 0.4 0.5 0.7 0.6 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If C is creep coefficient, f is original pre-stress in concrete, m is modular ratio, E is Young's modulus of steel and e is shrinkage strain, the combined effect of creep and shrinkage is: (1 - C) mf + eE (C - 1) mf + eE (C - 1) mf - eE (1 - C) mf - eE (1 - C) mf + eE (C - 1) mf + eE (C - 1) mf - eE (1 - C) mf - eE ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Spacing of stirrups in a rectangular beam, is Increased at the centre of the beam Increased at the ends Decreased towards the centre of the beam Kept constant throughout the length Increased at the centre of the beam Increased at the ends Decreased towards the centre of the beam Kept constant throughout the length ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C beam of 25 cm width has a clear span of 5 metres and carries a U.D.L. of 2000 kg/m inclusive of its self weight. If the lever arm of the section is 45 cm., the beam is Is safe with stirrups Safe in shear Needs revision of the section Is safe with stirrups and inclined members Is safe with stirrups Safe in shear Needs revision of the section Is safe with stirrups and inclined members ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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