RCC Structures Design In a combined footing if shear stress exceeds 5 kg/cm², the nominal stirrups provided are: 12 legged 8 legged 10 legged 6 legged 12 legged 8 legged 10 legged 6 legged ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The toe projection of foundation slabs is taken As one sixth of overall height of the wall As one third of the base Below ground surface Equal to heel slab As one sixth of overall height of the wall As one third of the base Below ground surface Equal to heel slab ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The number of treads in a flight is equal to None of these Risers in the flight Risers plus one Risers minus one None of these Risers in the flight Risers plus one Risers minus one ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design High strength concrete is used in pre-stressed member To overcome high bearing stresses developed at the ends To provide high bond stresses To overcome bursting stresses at the ends All listed here To overcome high bearing stresses developed at the ends To provide high bond stresses To overcome bursting stresses at the ends All listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If P kg/m² is the upward pressure on the slab of a plain concrete footing whose projection on either side of the wall is a cm, the depth of foundation D is given by D = 0.07775 aP D = 0.0775 aP D = 0.00775 aP D = 0.775 Pa D = 0.07775 aP D = 0.0775 aP D = 0.00775 aP D = 0.775 Pa ANSWER DOWNLOAD EXAMIANS APP
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