In a 4 pole. 20 kW, 200 V wave wound DC shunt generator, the current in each parallel path will be

• A. 100 A
• B. 25 A
• C. 10 A
• D. 50 A

Answer: (D)

Given
Power (P) = 20 kW = 20 × 103 W
Voltage (V) = 200 V
P = VI = I = P/V
I = (20 × 103)/200
I = 100A
For wave wound No. of Parallel Path = 2
Current in Each parallel Path for wave wound
I = 100/2 = 50 A