SSC JE Electrical 2019 with solution SET-2
In a 4 pole. 20 kW, 200 V wave wound DC shunt generator, the current in each parallel path will be

10 A
25 A
100 A
50 A

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SSC JE Electrical 2019 with solution SET-2
A series magnetic circuit will have

Different magnetic flux
Total reluctance of a series circuit = difference of the reluctances in different parts of the circuit
Two or more paths for magnetic flux
Same magnetic flux

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SSC JE Electrical 2019 with solution SET-2
The impedance at resonance offered by a parallel resonant circuit is

Minimum given by I/CR
Maximum given by I/CR
Minimum given by L/CR
Maximum given by L/CR

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SSC JE Electrical 2019 with solution SET-2
If a circular conductor carries a current of ‘I’ ampere having radius ‘r’ meter, then the magnetizing force at the center of the coil is given by

(1/r)*(At/Wb)
(1/4r)*(At/m)
(1/2r)*(At/m)
(1/r)*(At/m)

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