Given Power (P) = 20 kW = 20 × 103 W Voltage (V) = 200 V P = VI = I = P/V I = (20 × 103)/200 I = 100A For wave wound No. of Parallel Path = 2 Current in Each parallel Path for wave wound I = 100/2 = 50 A
The factor by which, the induced E.M.F gets reduced due to short pitching is called pitch factor or coil span factor denoted by Kc. It is given as Kc = cosα/2 given α = 60° Kc = cos60/2 Kc = cos30° Kc = √3/2