SSC JE Electrical 2019 with solution SET-2
The combined inductance of two coils connected in a series is 0.6H and 0.1H, depending on the relative directions of the currents to the coils. If one of the coils when isolated has a self-inductance of 0.2 H, then calculate the natural inductance?

0.15 H
1.5 H
0.015 H
0.125 H

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL ÷ Ise = Ia
IL = Ise + Ia
IL = Ise = Ia
IL ÷ Ise ÷ Ia

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SSC JE Electrical 2019 with solution SET-2
For indoor lighting the range of space : height is

3 :4
2 : 3
1 : 2
5 : 6

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SSC JE Electrical 2019 with solution SET-2
If a circular conductor carries a current of ‘I’ ampere having radius ‘r’ meter, then the magnetizing force at the center of the coil is given by

(1/2r)*(At/m)
(1/r)*(At/Wb)
(1/r)*(At/m)
(1/4r)*(At/m)

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