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SSC JE Electrical 2019 with solution SET-2

SSC JE Electrical 2019 with solution SET-2
Observe the given network and answer the question? The potential at point a = ?

E1 − I1R1
E1 − I1R1 & I3R3
I3R3
I2R2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

For the given network the potential at point a can be found by applying KVL.
For loop 1
Va = E1 − I1R1
Va = I3R3
For loop 2
Va = E2 − I2R2
 


SSC JE Electrical 2019 with solution SET-2
The urban service speed-time curve has no

Free-running period
Braking period
Coasting period
Acceleration period

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SSC JE Electrical 2019 with solution SET-2
Oxygen is a/an ____ gas?

Ferromagnetic
Paramagnetic
Inert
Diamagnetic

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Atoms or ions with unpaired electrons are attracted to a magnetic field; the more unpaired electrons, the greater is the attraction. Such substances are called paramagnetic. Molecular oxygen is a paramagnetic gas by virtue of its two unpaired electrons.
 

SSC JE Electrical 2019 with solution SET-2
Which of the following is NOT an expression to find self-inductance?

Nφ/I
Nφ
N2/S
N2μoμrA/I

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SSC JE Electrical 2019 with solution SET-2
A diode appears as in forward region of its characteristics?

An OFF switch
A capacitor
A high resistor
An ON switch

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

A P-N junction acts as a voltage-controlled switch. During forward biasied the p-n junction diode acts like an ON switch. When reverse biased, it acts like an OFF switch.
 


SSC JE Electrical 2019 with solution SET-2
Observe the given figure. Find Thevenin’s resistance as seen from open-circuited terminals?

16 Ω
32 Ω
8 Ω
4 Ω

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

To find the Thevenin’s resistance the current source is open-circuited and the voltage source is short-circuited.


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