SSC JE Electrical 2019 with solution SET-2
In the two-wattmeter method of three-phase power measurement of a balanced load, if the reading of one meter is −200W, then the power factor of the load is

Less than 0.5
Equal to zero
Greater than 0.5
Equal to 0.5

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SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL = Ise = Ia
IL = Ise + Ia
IL ÷ Ise = Ia
IL ÷ Ise ÷ Ia

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