SSC JE Electrical 2019 with solution SET-2
In the two-wattmeter method of three-phase power measurement of a balanced load, if the reading of one meter is −200W, then the power factor of the load is

Equal to 0.5
Less than 0.5
Greater than 0.5
Equal to zero

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SSC JE Electrical 2019 with solution SET-2
The 2’s complement of 1010101 is

0101011
0101010
1110011
1101010

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SSC JE Electrical 2019 with solution SET-2
If the connected light load in a house is 3000W and power sub-circuit load 6000W, then what is the total number of sub-circuits required?

6
4
1
3

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