SSC JE Electrical 2019 with solution SET-2
The impedance at resonance offered by a parallel resonant circuit is

Minimum given by L/CR
Maximum given by I/CR
Maximum given by L/CR
Minimum given by I/CR

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-2
If a circular conductor carries a current of ‘I’ ampere having radius ‘r’ meter, then the magnetizing force at the center of the coil is given by

(1/r)*(At/m)
(1/2r)*(At/m)
(1/4r)*(At/m)
(1/r)*(At/Wb)

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-2
Observe the figure and find the correct relation from the four given options?

i1 + i2 + i3 = i4 + i5 + i6
i1 + i2 + i6 = i4 + i5 + i3
i1 + i2 + i4 = i3 + i5 + i6
i4 + i2 + i3 = i1 + i5 + i6

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL = Ise = Ia
IL = Ise + Ia
IL ÷ Ise ÷ Ia
IL ÷ Ise = Ia

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP