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SSC JE Electrical 2019 with solution SET-2

SSC JE Electrical 2019 with solution SET-2
Which of the following is NOT an expression to find self-inductance?

N2μoμrA/I
Nφ
Nφ/I
N2/S

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SSC JE Electrical 2019 with solution SET-2
In a 4 pole. 20 kW, 200 V wave wound DC shunt generator, the current in each parallel path will be

25 A
50 A
100 A
10 A

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Power (P) = 20 kW = 20 × 103 W
Voltage (V) = 200 V
P = VI = I = P/V
I = (20 × 103)/200
I = 100A
For wave wound No. of Parallel Path = 2
Current in Each parallel Path for wave wound
I = 100/2 = 50 A
 

SSC JE Electrical 2019 with solution SET-2
In electric traction, the specific energy consumption is measured in

Ton-km watt-hour
Watt-hour/ ton-km
RPM/watt-hour
Watt-hour/RPM

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SSC JE Electrical 2019 with solution SET-2
If a zero-centered voltmeter has a scale from  5V to − 5V, then the span of it is

10V
5 V
−5 V
0 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Voltage Scale Span of  instrument = Vmax − Vmin
Given
Vmax = 5 V
Vmin = −5V
Span = 5 −(−5) = 10 V
 

SSC JE Electrical 2019 with solution SET-2
The candle power of a lamp placed normal to a working plane is 60 CP. Find the distance if the illumination is 15 lux?

1.5 meters
4 meters
2.5 meters
2 meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Candle Power of lamp = 60 CP
Illumination of lamp = 15 lux
Distance(D) = ? meters
Illumination of lamp = (candle power)/(distance)2
(D)2 = candle power/Illumination of lamp
(D)2 = 60/15 =4
D = √4
D = 2
 

SSC JE Electrical 2019 with solution SET-2
The function of compensation winding in AC series motor is to

Improve commutation
Reduced the armature resistance
Increase field flux
Reduce the effects of armature reaction

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