Observe the given figure. If the diode is an ideal diode, then what are the values of Io and Vo respectively?

• A. 0.2 A, 0V
• B. 0 A, 0.2 V
• C. 2 A, 10 V
• D. 10A, 2 V

Answer: (A)

Io = V/R = 20/100
Io = 0.2 A
Since the given diode is an ideal diode therefore there is no voltage drop across it.
Vo = Io × RD
Vo = 0.2 × 0
Vo = 0
Hence Io = 0.2 A & Vo = 0