Io = V/R = 20/100 Io = 0.2 A Since the given diode is an ideal diode therefore there is no voltage drop across it. Vo = Io × RD Vo = 0.2 × 0 Vo = 0 Hence Io = 0.2 A & Vo = 0
In the exclusive OR gate (XOR gate) has two inputs The ouput will be 1 when either input is 1 i.e X = 1 and Y = 1, but not when both the inputs are 1. If both the input is zero i.e X = 0 and Y = 0, then the output is 0.