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SSC JE Electrical 2019 with solution SET-2

SSC JE Electrical 2019 with solution SET-2
The function of compensation winding in AC series motor is to

Reduced the armature resistance
Increase field flux
Improve commutation
Reduce the effects of armature reaction

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SSC JE Electrical 2019 with solution SET-2
Observe the given figure. If the diode is an ideal diode, then what are the values of Io and Vo respectively?

0.2 A, 0V
2 A, 10 V
0 A, 0.2 V
10A, 2 V

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Io = V/R = 20/100
Io = 0.2 A
Since the given diode is an ideal diode therefore there is no voltage drop across it.
Vo = Io × RD
Vo = 0.2 × 0
Vo = 0
Hence Io = 0.2 A & Vo = 0
 

SSC JE Electrical 2019 with solution SET-2
The change in DC excitation of a synchronous motor will also change the

Speed of the motor
Load angle
Power factor
Supply voltage

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SSC JE Electrical 2019 with solution SET-2
A _____ transformer is usually mounted on a pole of plinth?

Potential
Distribution
Current
Power

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SSC JE Electrical 2019 with solution SET-2
  If two impedances are given as Z1 = 20∠60° and Z2 = 5∠30°, then Z1/Z2 = ?

100∠30°
100∠120°
4∠30°
5∠30°

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please check below image for solution.


SSC JE Electrical 2019 with solution SET-2
Observe the given table. The truth table represents gate?

OR
AND
XOR
NAND

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In the exclusive OR gate (XOR gate) has two inputs
The ouput will be 1 when either input is 1 i.e X = 1 and Y = 1, but not when both the inputs are 1.
If both the input is zero i.e X = 0 and Y = 0, then the output is 0.

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