SSC JE Electrical 2019 with solution SET-2
IL = Load Current, then the relation between these currents for a DC series generator is

IL ÷ Ise ÷ Ia
IL = Ise + Ia
IL = Ise = Ia
IL ÷ Ise = Ia

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SSC JE Electrical 2019 with solution SET-2
If a circular conductor carries a current of ‘I’ ampere having radius ‘r’ meter, then the magnetizing force at the center of the coil is given by

(1/r)*(At/Wb)
(1/2r)*(At/m)
(1/r)*(At/m)
(1/4r)*(At/m)

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SSC JE Electrical 2019 with solution SET-2
If the connected light load in a house is 3000W and power sub-circuit load 6000W, then what is the total number of sub-circuits required?

6
1
3
4

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