SSC JE Electrical 2019 with solution SET-2 If ‘V’ is the voltage phasor and ‘I’ is the current phasor, then VI represents Total power Reactive power Apparent power Active power Total power Reactive power Apparent power Active power ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Apparent Power (S): It is defined as the product of r.m.s value of voltage (V) and current (1). It is denoted by S.S = V/I Volt Ampere
SSC JE Electrical 2019 with solution SET-2 In Boolean algebra (A. Ā) + A A 1 Ā 0 A 1 Ā 0 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to Boolean algebra lawA. Ā = AA + A = ATherefore in the given question(A. Ā) + A = A + A = A
SSC JE Electrical 2019 with solution SET-2 In a 4 pole. 20 kW, 200 V wave wound DC shunt generator, the current in each parallel path will be 100 A 50 A 10 A 25 A 100 A 50 A 10 A 25 A ANSWER EXPLANATION DOWNLOAD EXAMIANS APP GivenPower (P) = 20 kW = 20 × 103 WVoltage (V) = 200 VP = VI = I = P/VI = (20 × 103)/200I = 100AFor wave wound No. of Parallel Path = 2Current in Each parallel Path for wave woundI = 100/2 = 50 A
SSC JE Electrical 2019 with solution SET-2 Which of the following is NOT an expression to find self-inductance? N2/S N2μoμrA/I Nφ/I Nφ N2/S N2μoμrA/I Nφ/I Nφ ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-2 In electric traction, the specific energy consumption is measured in Watt-hour/ ton-km Ton-km watt-hour RPM/watt-hour Watt-hour/RPM Watt-hour/ ton-km Ton-km watt-hour RPM/watt-hour Watt-hour/RPM ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-2 A coil of 360 turns is linked by a flux of 200 μWb. If the flux is reversed in 0.01 second, then find the EMF induced in the coil? 0.72 V 14.4 V 7.2 V 144 V 0.72 V 14.4 V 7.2 V 144 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given
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