RCC Structures Design If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor) M/100Q √(M/100Q) M/10√Q √(M/Q) M/100Q √(M/100Q) M/10√Q √(M/Q) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the size of a column is reduced above the floor, the main bars of the columns, are All of the listed here Stopped just below the floor level and separate lap bars provided Bent inward at the floor level Continued up All of the listed here Stopped just below the floor level and separate lap bars provided Bent inward at the floor level Continued up ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the average bending stress is 6 kg/cm² for M 150 grade concrete, the length of embedment of a bar of diameter d according to I.S. 456 specifications, is 58 d 48 d 28 d 38 d 58 d 48 d 28 d 38 d ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The modular ratio ‘m’ of a concrete whose permissible compressive stress is ‘C’, may be obtained from the equation. m = 3500/3C m = 1400/3C m = 2800/3C m = 700/3C m = 3500/3C m = 1400/3C m = 2800/3C m = 700/3C ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the maximum dip of a parabolic tendon carrying tension P is h and the effective length of the pre-stressed beam is L, the upward uniform pressure will be 8hl/p² 8hl/p 8hp/l² 8hp/l 8hl/p² 8hl/p 8hp/l² 8hp/l ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/3Sb l = dt/Sb l = dt/4Sb l = dt/2Sb l = dt/3Sb l = dt/Sb l = dt/4Sb l = dt/2Sb ANSWER DOWNLOAD EXAMIANS APP
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