RCC Structures Design If the maximum bending moment of a simply supported slab is M Kg.cm, the effective depth of the slab is (where Q is M.R. factor) √(M/100Q) M/10√Q √(M/Q) M/100Q √(M/100Q) M/10√Q √(M/Q) M/100Q ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A short column 20 cm × 20 cm in section is reinforced with 4 bars whose area of cross section is 20 sq. cm. If permissible compressive stresses in concrete and steel are 40 kg/cm² and 300 kg/cm², the Safe load on the column, should not exceed 412,000 kg 41,200 kg 4,120 kg None of these 412,000 kg 41,200 kg 4,120 kg None of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 16 cm² 17 cm² 14 cm² 15 cm² 16 cm² 17 cm² 14 cm² 15 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the permissible compressive and tensile stresses in a singly reinforced beam are 50 kg/cm² and 1400 kg/cm² respectively and the modular ratio is 18, the percentage area At of the steel required for an economic section, is 0.696 % 0.796 % 0.596 % 0.496 % 0.696 % 0.796 % 0.596 % 0.496 % ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The amount of reinforcement for main bars in a slab, is based upon Maximum shear force Minimum bending moment Minimum shear force Maximum bending moment Maximum shear force Minimum bending moment Minimum shear force Maximum bending moment ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is f = (P/'- (Z/M) f = (P/A) - (M/Z) f = (A/P) - (M/Z) f = (P/A) - (M/6Z) f = (P/'- (Z/M) f = (P/A) - (M/Z) f = (A/P) - (M/Z) f = (P/A) - (M/6Z) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS