RCC Structures Design The breadth of a ribbed slab containing two bars must be between 12 cm to 15 cm 8 cm to 10 cm 10 cm to 12 cm 6 cm to 7.5 cm 12 cm to 15 cm 8 cm to 10 cm 10 cm to 12 cm 6 cm to 7.5 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-cast pile generally used, is Square with corners chamfered Octagonal Square Circular Square with corners chamfered Octagonal Square Circular ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The toe projection of foundation slabs is taken As one third of the base Below ground surface Equal to heel slab As one sixth of overall height of the wall As one third of the base Below ground surface Equal to heel slab As one sixth of overall height of the wall ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 16 cm² 14 cm² 15 cm² 17 cm² 16 cm² 14 cm² 15 cm² 17 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed concrete member is preferred because All listed here Large size of long beams carrying large shear force need not be adopted Removal of cracks in the members due to shrinkage Its dimensions are not decided from the diagonal tensile stress All listed here Large size of long beams carrying large shear force need not be adopted Removal of cracks in the members due to shrinkage Its dimensions are not decided from the diagonal tensile stress ANSWER DOWNLOAD EXAMIANS APP
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