RCC Structures Design If the effective length of a 32 cm diameter R.C.C. column is 4.40 m, its slenderness ratio, is 55 50 40 45 55 50 40 45 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design For a ribbed slab All listed here Overall depth of the slab shall not exceed four times the breadth of the rib Clear spacing between ribs shall not be greater than 4.5 cm Width of the rib shall not be less than 7.5 cm All listed here Overall depth of the slab shall not exceed four times the breadth of the rib Clear spacing between ribs shall not be greater than 4.5 cm Width of the rib shall not be less than 7.5 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If depth of slab is 10 cm, width of web 30 cm, depth of web 50 cm, centre to centre distance of beams 3 m, effective span of beams 6 m, the effective flange width of the beam, is 300 cm 100 cm 200 cm 150 cm 300 cm 100 cm 200 cm 150 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed rectangular beam which carries two concentrated loads W at L/3 from either end, is provided with a bent tendon with tension P such that central one-third portion of the tendon remains parallel to the longitudinal axis, the maximum dip h is WL/2P WL/3P WL/4P WL/P WL/2P WL/3P WL/4P WL/P ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The thickness of base slab of a retaining wall generally provided, is One fourth of the width of the steam at the bottom Width of the stem at the bottom One half of the width of the stem at the bottom One-third of the width of the stem at the bottom One fourth of the width of the steam at the bottom Width of the stem at the bottom One half of the width of the stem at the bottom One-third of the width of the stem at the bottom ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] h = (W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = √(W/Aw) [(1 - sin φ)/(1 + sin φ)]² h = (W/Aw) [(1 - sin φ)/(1 + sin φ)] h = (W/Aw) [(1 + sin φ)/(1 + sin φ)] ANSWER DOWNLOAD EXAMIANS APP
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