Waste Water Engineering If 2% solution of a sewage sample is incubated for 5 days at 20°C and depletion of oxygen was found to be 5 ppm, B.O.D. of the sewage is None of these 225 ppm 200 ppm 250 ppm None of these 225 ppm 200 ppm 250 ppm ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The porosity of sediments in sewer pipes, is usually taken as 0.012 0.01 0.011 0.013 0.012 0.01 0.011 0.013 ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering For detecting the nitrates in sewage, the colour may be developed by adding Potassium permanganate None of these Sulphuric acid and napthamine Phenol-di -sulphuric acid and potassium hydroxide Potassium permanganate None of these Sulphuric acid and napthamine Phenol-di -sulphuric acid and potassium hydroxide ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The drainage area of a town is 12 hectares. Its 40% area is hard pavement ( K = 0.85), the 40% area is unpaved streets (K = 0.20) and the remaining is wooded areas (K = 0.15). Assuming the time of concentration for the areas as 30 minutes and using the formula Ps = 900/(t + 60) the maximum run off is 0.10 cumec 0.15 cumec 0.12 cumec 0.20 cumec 0.10 cumec 0.15 cumec 0.12 cumec 0.20 cumec ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering In a sludge digestion tank if the moisture content of sludge V1 litres is reduced from p1 % to p2 % the volume V2 is [(100 + P2)/(100 – P1)] V1 [(100 + P1)/(100 – P2)] V1 [(100 – P1)/(100 + P2)] V1 [(100 – P1)/(100 – P2)] V1 [(100 + P2)/(100 – P1)] V1 [(100 + P1)/(100 – P2)] V1 [(100 – P1)/(100 + P2)] V1 [(100 – P1)/(100 – P2)] V1 ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering ¾th or ¼th extra space is left in sewer pipes at maximum discharge for Large scale infiltration of storm water Unexpected increase in population All listed here Low estimates of the average and maximum flows Large scale infiltration of storm water Unexpected increase in population All listed here Low estimates of the average and maximum flows ANSWER DOWNLOAD EXAMIANS APP
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