Process Equipment and Plant Design Holes of a sieve tray are arranged in triangular pitch of __________ times the hole diameter. 10 to 15 5 to 10 2.5 to 5 1.5 to 2 10 to 15 5 to 10 2.5 to 5 1.5 to 2 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Pick out the wrong statement about the design of seive plate column and the bubble cap column. Weir length for a bubble cap plate is the same as that for the seive plate The downcomer design and the residence time in the downcomer is almost same for seive plate and bubble cap columns Weir height for a bubble cap plate column is the same as that for a seive plate column Weir height in case of a bubble cap plate ranges from 50 to 150 mm and is higher than the seive plate Weir length for a bubble cap plate is the same as that for the seive plate The downcomer design and the residence time in the downcomer is almost same for seive plate and bubble cap columns Weir height for a bubble cap plate column is the same as that for a seive plate column Weir height in case of a bubble cap plate ranges from 50 to 150 mm and is higher than the seive plate ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Welded joint efficiency in the design of chemical process equipment is taken as 0.85 0.75 0.95 0.55 0.85 0.75 0.95 0.55 ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Back-trapping in a distillation column results due to Low gas velocity Low reflux ratio High gas velocity Excessive liquid gradient over the tray Low gas velocity Low reflux ratio High gas velocity Excessive liquid gradient over the tray ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design In a cylinderical vessel subjected to internal pressure, the longitudinal stress σL and the circumferential stress, σh are related by σh = σL/2 No relation exists σh = σL σh = 2 σL σh = σL/2 No relation exists σh = σL σh = 2 σL ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Heat transfer co-efficient, hG(Kcal/hr.m² .°C) and mass velocity of air, G (kg/hr.m² ) for air flow parallel to the surface in case of constant drying rate in batch drying is related as hG = 0.0176G0.8. But when the flow of air perpendicular to the surface is encountered, this equation changes to HG = 1.004G0.37 1.004G0.8 0.0176G1.37 HG = 0.0176G0.37 HG = 1.004G0.37 1.004G0.8 0.0176G1.37 HG = 0.0176G0.37 ANSWER DOWNLOAD EXAMIANS APP
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