RCC Structures Design High strength concrete is used in pre-stressed member All listed here To provide high bond stresses To overcome bursting stresses at the ends To overcome high bearing stresses developed at the ends All listed here To provide high bond stresses To overcome bursting stresses at the ends To overcome high bearing stresses developed at the ends ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 17 cm² 14 cm² 16 cm² 15 cm² 17 cm² 14 cm² 16 cm² 15 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design On an absolutely rigid foundation base, the pressure will Be more at the edges of the foundation Be zero at the centre of the foundation Be uniform Not be uniform Be more at the edges of the foundation Be zero at the centre of the foundation Be uniform Not be uniform ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to I.S. : 456 specifications, the safe diagonal tensile stress for M 150 grade concrete, is 5 kg/cm² 20 kg/cm² 10 kg/cm² 15 kg/cm² 5 kg/cm² 20 kg/cm² 10 kg/cm² 15 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘A’ is the sectional area of a pre-stressed rectangular beam provided with a tendon pre-stressed by a force ‘P’ through its centroidal longitudinal axis, the compressive stress in concrete, is P/2A P/A A/P 2A/P P/2A P/A A/P 2A/P ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq D = W (a² - b²)/8a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/4abq D = W (a - b)/4a²bq ANSWER DOWNLOAD EXAMIANS APP