Concrete Technology and Design of Concrete Structures For a reinforced concrete section, the shape of shear stress diagram is rectangular above neutral axis and parabolic below neutral axis wholly parabolic parabolic above neutral axis and rectangular below neutral axis wholly rectangular rectangular above neutral axis and parabolic below neutral axis wholly parabolic parabolic above neutral axis and rectangular below neutral axis wholly rectangular ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The centroid of compressive force, from the extreme compression fiber, in limit state design lies at a distance of (where xu is the depth of neutral axis at the limit state of collapse) 0.367 xu 0.573 xu 0.446 xu 0.416 xu 0.367 xu 0.573 xu 0.446 xu 0.416 xu ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In the design of a front counterfort in a counterfort retaining wall, the main reinforcement is provided on i) bottom face near counterfort ii) top face near counterfort iii) bottom face near centre of span iv) top face near centre of span The correct answer is only (ii) both (i) and (iv) both (ii) and (iii) only (i) only (ii) both (i) and (iv) both (ii) and (iii) only (i) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The load factors for live load and dead load are taken respectively as 2.2 and 1.5 1.5 and 2.2 1.5 and 1.5 2.2 and 2.2 2.2 and 1.5 1.5 and 2.2 1.5 and 1.5 2.2 and 2.2 ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Shrinkage of concrete depends upon i) humidity of atmosphere ii) passage of time iii) stress The correct answer is only (iii) All (i), (ii) and (iii) (i) and (ii) (ii) and (iii) only (iii) All (i), (ii) and (iii) (i) and (ii) (ii) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by tcr – rcs = tct fcr fc5>fcr>fC fcr>fcs>fc. tcr – rcs = tct fcr fc5>fcr>fC fcr>fcs>fc. ANSWER DOWNLOAD EXAMIANS APP
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