Concrete Technology and Design of Concrete Structures The slab is designed as one way if the ratio of long span to short span is between 1 and 1.5 between 1.5 and 2 greater than 2 less than 1 between 1 and 1.5 between 1.5 and 2 greater than 2 less than 1 ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures According to IS : 456- 1978, minimum slenderness ratio for a short column is less than 18 more than 24 less than 12 between 18 and 24 less than 18 more than 24 less than 12 between 18 and 24 ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures Examine the following statements :i) Factor of safety for steel should be based on its yield stress,ii) Factor of safety for steel should be based on its ultimate stress,iii) Factor of safety for concrete should be based on its yield stress,iv) Factor of safety for concrete should be based on its ultimate stress.The correct statements are (ii) and (iv) (ii) and (iii) (i) and (iii) (i) and (iv) (ii) and (iv) (ii) and (iii) (i) and (iii) (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures If nominal shear stress tv exceeds the design shear strength of concrete xc, the nominal shear reinforcement as per IS : 456-1978 shall be provided for carrying a shear stress equal to xc xv Tv + Tc xc xv Tv + Tc ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures In the design of a front counterfort in a counterfort retaining wall, the main reinforcement is provided on i) bottom face near counterfort ii) top face near counterfort iii) bottom face near centre of span iv) top face near centre of span The correct answer is both (ii) and (iii) only (ii) only (i) both (i) and (iv) both (ii) and (iii) only (ii) only (i) both (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Concrete Technology and Design of Concrete Structures The relation between modulus of rupture fcr, splitting strength fcs and direct tensile strength fcl is given by fc5>fcr>fC fcr>fcs>fc. fcr tcr – rcs = tct fc5>fcr>fC fcr>fcs>fc. fcr tcr – rcs = tct ANSWER DOWNLOAD EXAMIANS APP
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