MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Dimnished Benifited Suppresed Ambience Dimnished Benifited Suppresed Ambience ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Choose the word which best expresses the similar meaning of the given word " CALLOW" Immature Calm Mature Sophisticated Immature Calm Mature Sophisticated ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The operating system is the most common type of ___ Communication Firmware System Software Application Software Communication Firmware System Software Application Software ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) While selecting the gas for a circuit breaker, the property of gas that should be considered is its(i) dielectric strength(ii) non-inflammability(iii) non-toxicity (i) and (ii) only (i) and (iii) only (i), (ii) and (iii) (i) only (i) and (ii) only (i) and (iii) only (i), (ii) and (iii) (i) only ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Properties of gas while selecting circuit breaker,1. Dielectric strength.2. Thermal conductivity.3. Arc quenching.4. Electrical properties.5. Chemical properties. Toxicity of arc products.
MGVCL Exam Paper (30-07-2021 Shift 1) By inserting a plate of dielectric material between the plates of a parallel plate capacitor at constant potential, the energy stored in the capacitor is increased five times. The dielectric constant of the material is 25 1/5 5 1/25 25 1/5 5 1/25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Energy stored by capacitor, Q = ½CV²Dielectric constant is directly proportional to C and capacitance is proportional to the dielectrical constant
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 150 kW 300 kW 450 kW 600 kW 150 kW 300 kW 450 kW 600 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
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