MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Ambience Benifited Suppresed Dimnished Ambience Benifited Suppresed Dimnished ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The power factor angle of a purely inductive circuit is 60° 90° 45° 30° 60° 90° 45° 30° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Power factor for purely inductive circuit is 0 and power factor angle is 90 degree.Power factor for purely capacitive circuit is 0 and power factor angle is 90 degreePower factor for purely resistive circuit is 1 and power factor angle is 0 degree
MGVCL Exam Paper (30-07-2021 Shift 1) જ્વાળા: ધુમાડો:: બરફ : ___ બાષ્પ ગરમી તાપમાન શીતળતા બાષ્પ ગરમી તાપમાન શીતળતા ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Murray loop test is performed on a faulty cable 300 m long. At balance, the resistance connected to the faulty core was set at 15 Ω and the resistance of the resistor connected to the sound core was 45 Ω. Calculate the distance of the fault point from the test end. 75 m 225 m 450 m 150 m 75 m 225 m 450 m 150 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Where,R2 is the resistance connected to the faulty core in ohmR2 is the resistance of the resistor connected to the sound core in ohmR1 Distance of fault location (Lx) = R2/(R1 + R2)*(2*L)= (15/60)*600= 150 m
MGVCL Exam Paper (30-07-2021 Shift 1) Two-wattmeter method is used to measure the power taken by a 3-phase induction motor on no load. The wattmeter readings are 375 W and –50 W. Calculate the reactive power taken by the load. 425√3 VAR 425/√3 VAR 325/√3 VAR 325√3 VAR 425√3 VAR 425/√3 VAR 325/√3 VAR 325√3 VAR ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Reactive power taken, Q = √3*(W1 - W2)Q = √3*(375 + 50)Q = √3*425 kVAR
MGVCL Exam Paper (30-07-2021 Shift 1) An alternator is supplying load of 300 kW at a power factor of 0.5 lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading? 600 kW 150 kW 300 kW 450 kW 600 kW 150 kW 300 kW 450 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = S*cosφS = P/cosφS = 300/0.5S = 600 kVAFor same kVA rating and unity power factor,P = 600*1P = 600 kWPextra = 600 - 300Pextra = 300 kW
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