Refrigeration and Air Conditioning During adiabatic saturation process on unsaturated air ___ remains constant. Dew point temperature Relative humidity Wet bulb temperature Dry bulb temperature Dew point temperature Relative humidity Wet bulb temperature Dry bulb temperature ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The lower horizontal line of the refrigeration cycle plotted on pressure-enthalpy diagram represents Metering of the refrigerant liquid Compression of the refrigerant vapour Evaporation of the refrigerant liquid Condensation of the refrigerant vapour Metering of the refrigerant liquid Compression of the refrigerant vapour Evaporation of the refrigerant liquid Condensation of the refrigerant vapour ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Accumulators should have adequate volume to store refrigerant charge at least 0.75 0.1 0.25 0.5 0.75 0.1 0.25 0.5 ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The ratio of actual mass of water vapour in a given volume of moist air to the mass of water vapour in the same volume of saturated air at the same temperature and pressure, is called Degree of saturation Humidity ratio Relative humidity Absolute humidity Degree of saturation Humidity ratio Relative humidity Absolute humidity ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning When the lower temperature of a refrigerating machine is fixed, then the coefficient of performance can be improved by Lowering the higher temperature Raising the higher temperature Operating the machine at lower speeds Operating the machine at higher speeds Lowering the higher temperature Raising the higher temperature Operating the machine at lower speeds Operating the machine at higher speeds ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A refrigerating system operating on reversed Brayton refrigeration cycle is used for maintaining 250 K. If the temperature at the end of constant pressure cooling is 300 K and rise in the temperature of air in the refrigerator is 50 K, then the net work of compression will be (assume air as working substance with Cp = 1 kJ/kg) 125 kJ/kg 100 kJ/kg 25 kJ/kg 50 kJ/kg 125 kJ/kg 100 kJ/kg 25 kJ/kg 50 kJ/kg ANSWER DOWNLOAD EXAMIANS APP
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