Refrigeration and Air Conditioning The capacity of a domestic refrigerator is in the range of 1 to 3 TR 5 to 7 TR 3 to 5 TR 0.1 to 0.3 TR 1 to 3 TR 5 to 7 TR 3 to 5 TR 0.1 to 0.3 TR ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The operating temperature of a cold storage is -2°C. The heat leakage from the surrounding is 30 kW for the ambient temperature of 40°C. The actual C.O.P. of refrigeration plant used is one fourth that of ideal plant working between the same temperatures. The power required to drive the plant is 1.86 kW 7.44 kW 3.72 kW 18.6 kW 1.86 kW 7.44 kW 3.72 kW 18.6 kW ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The vapour compression refrigerator employs the following cycle Reversed Carnot Rankine Reversed Rankine Carnot Reversed Carnot Rankine Reversed Rankine Carnot ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The capillary tube is not used in large capacity refrigeration systems because Required pressure drop cannot be achieved It is made of copper Capacity control is not possible Cost is too high Required pressure drop cannot be achieved It is made of copper Capacity control is not possible Cost is too high ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A refrigeration system Removes heat from a low temperature body and delivers it to a high temperature body Removes heat from a high temperature body and delivers it to a low temperature body Rejects energy to a low temperature body None of the listed here Removes heat from a low temperature body and delivers it to a high temperature body Removes heat from a high temperature body and delivers it to a low temperature body Rejects energy to a low temperature body None of the listed here ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning Relative humidity is given by (where pv = Partial pressure of water vapour, pb = Barometric pressure, ps = Pressure of saturated air, pd = Pressure at dry bulb temperature, pw = Saturation pressure corresponding to wet bulb temperature, and μ = Degree of saturation) 0.622 Pv / (Pb - Pv) None of these [Pv (Pb - Pd)]/ [Pd (Pb - Pv)] μ/[1 - (1 - μ) (Ps/Pb)] 0.622 Pv / (Pb - Pv) None of these [Pv (Pb - Pd)]/ [Pd (Pb - Pv)] μ/[1 - (1 - μ) (Ps/Pb)] ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS