Refrigeration and Air Conditioning The operating temperature of a cold storage is -2°C. The heat leakage from the surrounding is 30 kW for the ambient temperature of 40°C. The actual C.O.P. of refrigeration plant used is one fourth that of ideal plant working between the same temperatures. The power required to drive the plant is 1.86 kW 7.44 kW 18.6 kW 3.72 kW 1.86 kW 7.44 kW 18.6 kW 3.72 kW ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning A refrigerating system operating on reversed Brayton refrigeration cycle is used for maintaining 250 K. If the temperature at the end of constant pressure cooling is 300 K and rise in the temperature of air in the refrigerator is 50 K, then the net work of compression will be (assume air as working substance with Cp = 1 kJ/kg) 25 kJ/kg 100 kJ/kg 125 kJ/kg 50 kJ/kg 25 kJ/kg 100 kJ/kg 125 kJ/kg 50 kJ/kg ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The C.O.P. of an absorption type refrigerator is given by (where T₁ = Temperature at which the working substance receives heat, T₂ = Temperature of cooling water, and T₃ = Evaporator temperature) [T₁ (T₁ - T₂)] / [T₃ (T₂ - T₃)] [T₃ (T₂ - T₃)] / [T₁ (T₁ - T₂)] [T₁ (T₂ - T₃)] / [T₃ (T₁ - T₂)] [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)] [T₁ (T₁ - T₂)] / [T₃ (T₂ - T₃)] [T₃ (T₂ - T₃)] / [T₁ (T₁ - T₂)] [T₁ (T₂ - T₃)] / [T₃ (T₁ - T₂)] [T₃ (T₁ - T₂)]/ [T₁ (T₂ - T₃)] ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning In aqua ammonia absorption refrigeration system, incomplete rectification leads to accumulation of water in Absorber Evaporator Condenser None of these Absorber Evaporator Condenser None of these ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance (C.O.P.) of a refrigerator working as a heat pump is given by ( O.P)P = ( ( O.P.)R + 2 O.P)R O.P)P = ( O.P.)P = ( ( O.P.)P = ( O.P)R - 1 ( O.P.)R + 1 ( O.P)P = ( ( O.P.)R + 2 O.P)R O.P)P = ( O.P.)P = ( ( O.P.)P = ( O.P)R - 1 ( O.P.)R + 1 ANSWER DOWNLOAD EXAMIANS APP
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