Area Problems The perimeter of two square is 12 cm and 24 cm. The area of the bigger square is how many times that of the smaller? 3 times 4 times 5 times 2 times 3 times 4 times 5 times 2 times ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of area of 2 squares = (ratio of perimeter of 2 squares)2= (24/12)2= 4
Area Problems A cost of cultivating a square field at a rate of ? 135 per hectare is ? 1215. The cost of putting a fence around it at the rate of 75 paise per meter wouldbe ? 360 ? 1800 ? 900 ? 810 ? 360 ? 1800 ? 900 ? 810 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the field =1215/135 = 9 hec= 90000 m2 [1 hec =10000 m2]? Side of the field = ?90000 = 300 mPerimeter of the field = 4 x 300 = 1200 mNow, cost of putting a fence around field = (1200 x 75)/100 = ? 900
Area Problems Diagonals of a rhombus area 1 m and 1.5 m in lengths. The area of the rhombus is 0.375 m2 1.5 m2 1.5 m2 0.75 m2 0.375 m2 1.5 m2 1.5 m2 0.75 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus =(d1 x d2)/2 =(1 x 1.5)/2 m2= 0.75 m2
Area Problems If the diagonals of a rhombus are 4.8 cm 1.4 cm, then what is the perimeter of the rhombus? 5 cm 20 cm 12 cm 10 cm 5 cm 20 cm 12 cm 10 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Perimeter of rhombus= 2 ? d12 + d22 = 2 ?(4.8)2 + (1.4)2= 2 ?23.04 + 1.96 = 2 ?25 = 2 x 5 = 10 cm
Area Problems Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is 40° 36° 18° 54° 40° 36° 18° 54° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let First angle = 3kSecond angle = 4kThird angle = 5k and Fourth angle = 8kWe know 3k + 4k + 5k + 8k = 360°? 20k = 360° ? k = 18 °Measure of smallest angle = 3k =3 x 18 ° = 54 °
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