Area Problems The perimeter of two square is 12 cm and 24 cm. The area of the bigger square is how many times that of the smaller? 2 times 5 times 3 times 4 times 2 times 5 times 3 times 4 times ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of area of 2 squares = (ratio of perimeter of 2 squares)2= (24/12)2= 4
Area Problems A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is Rs. 558 Rs. 458 Rs. 258 Rs. 358 Rs. 558 Rs. 458 Rs. 258 Rs. 358 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area to be plastered = 2 l + b × h + l × b = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m Cost of plastering = 744 × 75 100 = R s . 558
Area Problems Three circles of radius 3.5cm are placed in such a way that each circle touches the other two. The area of the portion enclosed by the circles is 1.567 1.967 1.867 1.767 1.567 1.967 1.867 1.767 ANSWER DOWNLOAD EXAMIANS APP
Area Problems A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is? 5.25 meters 10.5 meters 21 meters 7 meters 5.25 meters 10.5 meters 21 meters 7 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let outer radius be R and inner radius be r.Then from question 2?R - 2?r = 66? 2? (R-r) = 66? (2 x 22)/7 x (R - r) = 66? (R-r) = (66 x 7) / 44= 10.5 m
Area Problems The area of sector of a circle of radius 5 cm, formed by an arc of length 3.5 cm is? 55 sq.cms 35 sq.cms 8. 75 sq.cms 17.5 sq.cms 55 sq.cms 35 sq.cms 8. 75 sq.cms 17.5 sq.cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of sector = ( arc length x radius ) / 2 cm2= (3.5 x 5 ) / 2= 8.75 cm2
Area Problems A person observed that he required 30 s time to cross a circular ground along its diameter than to cover it once along the boundary. If his speed was 30m/min, than the radius of the circular ground is (take ? = 22/7) 3.5 m 10.5 m 7.5 m 5.5 m 3.5 m 10.5 m 7.5 m 5.5 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the radius of circular field = r m.Speed of person in m/s = 30/60 = 1/2m/sAccording to the question,[(2?r) /(1/2)] - [(2r)/(1/2)] = 30? 4?r - 4r = 30? [4 x (22/7) - 4]r =30? (125 - 4)r = 30 ? (8.5)r = 30? r = 30/8.5 = 3.5 m
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