Area Problems Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is 40° 18° 54° 36° 40° 18° 54° 36° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let First angle = 3kSecond angle = 4kThird angle = 5k and Fourth angle = 8kWe know 3k + 4k + 5k + 8k = 360°? 20k = 360° ? k = 18 °Measure of smallest angle = 3k =3 x 18 ° = 54 °
Area Problems In a rhombus, whose area is 144 sq.cmone of its diagonal is twice as long as the other, The lengths of its diagonals are? 6 ?2 cm, 12?2 cm 12 cm, 24 cm 24 cm, 48 cm 6 cm, 12 cm 6 ?2 cm, 12?2 cm 12 cm, 24 cm 24 cm, 48 cm 6 cm, 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus = (d1 x d2) / 2? (d x 2d ) / 2 = 144? d2 = 144? d = 12 ? Length of diagonal = 12 cm, 24 cm
Area Problems The ratio of the radii of two circle is 1:3 the radio of their areas is? None of these 1:3 1:6 1:9 None of these 1:3 1:6 1:9 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The Radio of areas = area of first circle : area of 2nd circle= ?r2 / ?(3r)2= ?r2/ 9 ?r2= 1/9 = 1: 9
Area Problems The circumferences of two concentric are 176 m and 132 m respectively. what is the difference between their radii? 5 meter 8 meter 7 meter 44 meter 5 meter 8 meter 7 meter 44 meter ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 2?R - 2?r = (176-132)? 2?(R-r) = 44? R-r = ( 44 x 7 )/ (2 x 22)= 7 m
Area Problems A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field? 90/7 min 230/7 min 110/7 min 220/7 min 90/7 min 230/7 min 110/7 min 220/7 min ANSWER EXPLANATION DOWNLOAD EXAMIANS APP speed = 12 km/h = 12 × 5 18 = 10 3 m / s distance covered = 20 × 2 × 22 7 × 50 = 44000 7 m time taken = distance /speed = 44000 7 × 3 10 s e c = 4400 × 3 7 × 1 60 m i n = 220 7 m i n
Area Problems One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is? 20 m 2 15 m2 12 m2 4?5 m2 20 m 2 15 m2 12 m2 4?5 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2
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