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Area Problems

Area Problems
The ratio of the area of square of side a and equilateral triangle of side a is?

4 :3
4 : ?3
2 :1
2 : ?3

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of area = a2/ ?(3/4) a2= 4/?3 = 4:?3

Area Problems
The cost of cultivating a square field at the rate of Rs. 160 per hectare is Rs. 1440. the cost of putting a fence around it at 75 paisa per meter is?

Rs. 360
Rs. 810
Rs. 1800
Rs. 900

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = 1440 / 160 hectares = 9 hectares = 90000 m2? One side = ?90000 m = 300 mSo perimeter = 4 x 300 m = 1200 m ? Cost of fencing = Rs (1200 x 75) / 100= Rs. 900

Area Problems
The length of a rectangle room is 4 meters . if it can be partitioned into two equal square rooms . what is the length of each partition in meters?

1
4
Data inadequate
2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the width of the room be x membersThen, its area = (4x) m2Area of each new square room = (2x)m2Let the side of each new room = y metersThen, y2 = 2xClearly, 2x is a complete square when x=2? y2 = 4? y = 2 m .

Area Problems
What is the area of a square having perimeter 68 cm?

284 sq cm
361 sq cm
269 sq cm
289 sq cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

According to the question,4a = 68 [ where a = side]?a = 68/4 = 17 cm? Required area = a2= (17)2 = 289 sq cm

Area Problems
If the sides of a squares is increased by 25%, then the area of the squares will be increased by

56.25%
53.75%
50%
125%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%

Area Problems
A rectangular carpet has an area of 120 sq. m and a perimeter of 46 m . The length of its diagonal is?

16 m
17 m
20 m
15 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = a metres and breadth = b metres Then, 2(a+b)= 46 ? (a+b) =23 and ab =120 ? Diagonal = ?a2 + b2?(23)2-2 x 120?289 = 17 m

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