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Area Problems

Area Problems
The ratio of the area of square of side a and equilateral triangle of side a is?

2 : ?3
4 :3
4 : ?3
2 :1

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Ratio of area = a2/ ?(3/4) a2= 4/?3 = 4:?3

Area Problems
How many circular plates of diameter d be taken out of a square plate of side 2d with minimum loss of material?

6
2
8
5

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of square plate = (Side)2 = (2d)2= 4d2Area of circular plate = ? (d/2)2= ?d2/4? Number of square plates = [(4d2)/4] / [(?d2)/4]= (4 x 4)/? ? 5Since, nearest integer value is 5.

Area Problems
The area of a rectangular field is 15 time the sum of its length and breadth. If the length of that field is 40 m, what is the breadth of that field?

32 m
25 m
24 m
28 m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length ot rectangle = 40 mLet breadth of = kThen, according of the question, (40 + k)15 = 40k ? 600 + 15k = 40k ? 25k = 600? k = 24 m

Area Problems
A veranda 40 meters long 15 meters broad is to paved with stones each measuring 6 dm by 5 dm. the number of stones required is?

1000
3000
2000
None of these

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length = (40 x 10 ) dm = 400 dm.Breadth = (15 x 10 ) dm = 150 dm.Area of veranda = (400 x 150 ) dm2Area of one stone = (6 x 5 ) dm2? Required number of stones = (400 x 150) /(6 x 5) = 2000

Area Problems
A hall 20 m long and 15 m broad is surrounded by a verandah of uniform width of 2.5 m. the cost of flooring the verandah at the rate of 3.50 per sq. meter is?

Rs. 500
Rs. 600
Rs. 800
Rs. 700

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of verandah = [(25 x 20) -(20 x 15)] m2= 200 m2? Cost of flooring = Rs. (200 x 3.50)= Rs. 700

Area Problems
In a circle of radius 21 cm an arc subtends an angle of 72° at the centre. The length of the arc is?

19.8 cm
13.2 cm
26.4 cm
21.6 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Arc length = 2?r (?° / 360°) = 2 x (22/7) x 21 x (72° / 360°) cm= 26.4 cm

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