Area Problems The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base. 3 cm 2 cm 4 cm 1 cm 3 cm 2 cm 4 cm 1 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, area = 10 sq cm, perpendicular = 20 cm and base = ? area = (base x Perpendicular) / 2 ? 10 = (base x 20) / 2 ? base = 1 cm
Area Problems The area of circle is 38.5 sq. cm. Its circumference is? 121 cm 6.20 cm 22 cm 11 cm 121 cm 6.20 cm 22 cm 11 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? ( 22 x r2) / 7 = 38.5? r2 =(38.5 x 7) /22? r = 3.5 cm? Circumference = 2 x (22/7) x 3.5 cm= 22 cm
Area Problems If 88 m wire is required to fence a circular plot of land, then the area of the plot is? 616 m2 None of these 526 m2 556 m2 616 m2 None of these 526 m2 556 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of circular plot= 88 m? 2 x (22/7) x r = 88? r = 88 x (7/22) x (1/2) = 14 m Now area = ?r2=( 22/7) x 14 x 14 m2= 616 m2
Area Problems Area of a square with side x is equal to the area of a triangle with base x. The altitude of the triangle is? x/2 4x x 2x x/2 4x x 2x ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let h be the altitude of triangle.So area of triangle = (1/2)xh area of square = x2From question area of square = area of triangle x2 = (1/2)xh ? h = (2x2)/x = 2x
Area Problems A hall 20 m long and 15 m broad is surrounded by a verandah of uniform width of 2.5 m. the cost of flooring the verandah at the rate of 3.50 per sq. meter is? Rs. 700 Rs. 600 Rs. 800 Rs. 500 Rs. 700 Rs. 600 Rs. 800 Rs. 500 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of verandah = [(25 x 20) -(20 x 15)] m2= 200 m2? Cost of flooring = Rs. (200 x 3.50)= Rs. 700
Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? None of these 13 cm 12 cm 14cm None of these 13 cm 12 cm 14cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
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