Area Problems If the diagonals of a rhombus are 4.8 cm 1.4 cm, then what is the perimeter of the rhombus? 10 cm 20 cm 5 cm 12 cm 10 cm 20 cm 5 cm 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Perimeter of rhombus= 2 ? d12 + d22 = 2 ?(4.8)2 + (1.4)2= 2 ?23.04 + 1.96 = 2 ?25 = 2 x 5 = 10 cm
Area Problems The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is 154 49 1078 378 154 49 1078 378 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The diameter is equal to the shortest side of the rectangle. So radius= 14/2 = 7cm. Therefore, area of circle = (r)2 = (22/7) x 49 = 154 cm2
Area Problems Diagonals of a rhombus area 1 m and 1.5 m in lengths. The area of the rhombus is 1.5 m2 1.5 m2 0.75 m2 0.375 m2 1.5 m2 1.5 m2 0.75 m2 0.375 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of rhombus =(d1 x d2)/2 =(1 x 1.5)/2 m2= 0.75 m2
Area Problems The diagonal of a rectangle is √41 cm and its area is 20 sq. cm. The perimeter of the rectangle must be: 18 cm 20 cm 9 cm 41 cm 18 cm 20 cm 9 cm 41 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP √l2 + b2 = √41. Also, lb = 20. (l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81 ⟹ (l + b) = 9. ∴ Perimeter = 2(l + b) = 18 cm
Area Problems The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is? 18 sq. meters . 6 sq. meters . 9 sq. meters . 12 sq. meters . 18 sq. meters . 6 sq. meters . 9 sq. meters . 12 sq. meters . ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2
Area Problems If the side of a square is increased by 25%, then how much percent does its area get increased? 156.25 125 50 56.25 156.25 125 50 56.25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let area 100 m2Then, side = 10 m New side = 125 % of 10= (125/100) x 10= 12.5 m New area = 12.5 x 12.5 m2=(12.5)2 sq. m? Increase in area = (12.5)2 - (10)2 m2= 22.5 x 2.5 m2=56.25 m2% Increase = 56.25 %
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