Area Problems If the diagonals of a rhombus are 4.8 cm 1.4 cm, then what is the perimeter of the rhombus? 5 cm 12 cm 10 cm 20 cm 5 cm 12 cm 10 cm 20 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Perimeter of rhombus= 2 ? d12 + d22 = 2 ?(4.8)2 + (1.4)2= 2 ?23.04 + 1.96 = 2 ?25 = 2 x 5 = 10 cm
Area Problems What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad? 820 840 814 844 820 840 814 844 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. Area of each tile = (41 x 41) cm2. ∴ Required number of tiles = ❨ 1517 x 902 ❩ = 814
Area Problems Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm? 121 sq.com 164 sq.com 186 sq.com 154 sq.com 121 sq.com 164 sq.com 186 sq.com 154 sq.com ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides) = 1/2 x (12 + 10) x 14 = 22 x 14/2 = 22 x 7 = 154 sq. cm
Area Problems The base of right-angled triangle is 5 meters and hypotenuse is 13 meters . Its area will be? None of these 25m2 28 m2 30m2 None of these 25m2 28 m2 30m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Altitude = ?(13)2 - (5)2= ?144 = 12m ? Area of the triangle = (5 x 12 ) / 2 m2= 30m2
Area Problems How many circular plates of diameter d be taken out of a square plate of side 2d with minimum loss of material? 5 8 2 6 5 8 2 6 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of square plate = (Side)2 = (2d)2= 4d2Area of circular plate = ? (d/2)2= ?d2/4? Number of square plates = [(4d2)/4] / [(?d2)/4]= (4 x 4)/? ? 5Since, nearest integer value is 5.
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 4 meters 3 meters None of these 15 meters 4 meters 3 meters None of these 15 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
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