Area Problems A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is rs.258 rs.158 rs.358 rs.58 rs.258 rs.158 rs.358 rs.58 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m cost of graveling = 344 x (75/100) = Rs. 258
Area Problems Area of a four walls a room is 168 Sq. meters . The breadth and height of a room are 8 meters and 6 meters respectively . The length of the room is? 3.5 meters 6 meters 14 meters 12 meters 3.5 meters 6 meters 14 meters 12 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of a four walls = 2(l + 8) x 6 = 168m2? (l + 8) = 14? l = 14-8= 6 meters
Area Problems Find the area of a rectangle having 15m length and 8m breadth. 115 sq m 120 sq m 111 sq m 125 sq m 115 sq m 120 sq m 111 sq m 125 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems A tank is 25m long 12m wide and 6m deep. The cost of plastering its walls and bottom at 75 paise per sq m is Rs. 258 Rs. 558 Rs. 358 Rs. 458 Rs. 258 Rs. 558 Rs. 358 Rs. 458 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area to be plastered = 2 l + b × h + l × b = 2 25 + 12 × 6 + 25 × 12 = 744 s q . m Cost of plastering = 744 × 75 100 = R s . 558
Area Problems The area of circle inscribed in an equilateral triangle is 462 cm . The perimeter of the triangle is? 42 ? 3 cms 126 cms 72.6 cms 168 cms 42 ? 3 cms 126 cms 72.6 cms 168 cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 22/7 x r2 = 462? r2 = (462 x 7) /22 = 147? r = 7?3 cm ? Height of the triangle = 3r = 21?3 cmNow, ? a2 = a2/4 + (3r)2? 3a2/4 = (21?3)2? a2 = (1323 x 4)/3? a = 21x 2 = 42 cm? Perimeter = 3a = 3 x 42=126 cm
Area Problems The wheel of an engine turns 350 times round its axle to cover a distance of 1.76 km. The diameter of the wheel is 3 cm 9 cm 3?3 cm ?3 cm 3 cm 9 cm 3?3 cm ?3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance covered in 1 round = (Total Distance) / (Total round)= (1.76 x 1000)/350= 176/35 m ? 2?r = (1.76 x 100) / 35 cm2? = Diameter = 17600 x 7/22 x 35 = 160 cm
EXAMIANS