Microprocessor A microprocessor differentiates between op code, data/address at any time by the sequence in which memory contents are fetched by it the stack pointer the program counter its internal registers the sequence in which memory contents are fetched by it the stack pointer the program counter its internal registers ANSWER DOWNLOAD EXAMIANS APP
Microprocessor The reason for the presence of ALE pin in 8085, but not in 6800 is that 8085 has multiplexed bus, whereas 6800 does not have 8085 uses I/O mapped I/O, whereas 6800 uses memory mapped I/O None 8085 has 5 interrupts lines, whereas 6800 has only two 8085 has multiplexed bus, whereas 6800 does not have 8085 uses I/O mapped I/O, whereas 6800 uses memory mapped I/O None 8085 has 5 interrupts lines, whereas 6800 has only two ANSWER DOWNLOAD EXAMIANS APP
Microprocessor Temporary registers in 8085 are B and C. W and Z. D and E. H and L. B and C. W and Z. D and E. H and L. ANSWER DOWNLOAD EXAMIANS APP
Microprocessor Let the content of register C be 00000000 before the instruction DCR C is executed. The content of register C after the after the execution of this instruction will be 00000001 None 11111111 00000000 00000001 None 11111111 00000000 ANSWER DOWNLOAD EXAMIANS APP
Microprocessor When .9432 E – 4 is subtracted from .5452 E – 3 in normalized floating point mode None of the numbers is changed Both Ihe numbers are changed and their exponents are, made equal to -5 .9432 E – 4 is changed to .09432 E – 3 and .5452 E – 3 is not changed .5452 E – 3 is changed to 5.452 E – 4 but .9432 E – 4 is not changed None of the numbers is changed Both Ihe numbers are changed and their exponents are, made equal to -5 .9432 E – 4 is changed to .09432 E – 3 and .5452 E – 3 is not changed .5452 E – 3 is changed to 5.452 E – 4 but .9432 E – 4 is not changed ANSWER DOWNLOAD EXAMIANS APP
Microprocessor Using DeMorgan’s Theorem we can convert any AND-OR structure into NAND-NAND NOR-NAND OR-NAND NAND-NOR NAND-NAND NOR-NAND OR-NAND NAND-NOR ANSWER DOWNLOAD EXAMIANS APP
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