RCC Structures Design A column is regarded as long column if the ratio of its effective length and lateral dimension, exceeds 25 15 10 20 25 15 10 20 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The length of the straight portion of a bar beyond the end of the hook, should be at least Four times the diameter Seven times the diameter Twice the diameter Thrice the diameter Four times the diameter Seven times the diameter Twice the diameter Thrice the diameter ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 15 cm² 16 cm² 14 cm² 17 cm² 15 cm² 16 cm² 14 cm² 17 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is Kx (1 - x/l) + bw K/x (1 + x/d) + bw All listed here Kx (1 + x/l) + bw Kx (1 - x/l) + bw K/x (1 + x/d) + bw All listed here Kx (1 + x/l) + bw ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A pre-stressed rectangular beam which carries two concentrated loads W at L/3 from either end, is provided with a bent tendon with tension P such that central one-third portion of the tendon remains parallel to the longitudinal axis, the maximum dip h is WL/3P WL/P WL/4P WL/2P WL/3P WL/P WL/4P WL/2P ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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