RCC Structures Design A column is regarded as long column if the ratio of its effective length and lateral dimension, exceeds 15 20 25 10 15 20 25 10 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the bearing capacity of soil is 10 tonnes/cm² and the projection of plain concrete footing from walls, is a cm, the depth D of footing is D = 0.775 √a D = 0.0775 a D = 0.775 a D = 0.775 a² D = 0.775 √a D = 0.0775 a D = 0.775 a D = 0.775 a² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The pitch of the main bars in a simply supported slab, should not exceed its effective depth by Four times Six times Five times Three times Four times Six times Five times Three times ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If d is the diameter of a bar, ft is allowable tensile stress and fb, is allowable bond stress, the bond length is given by ft .d/4fb (π/4). (ft .d3/fb) π ft .d²/fb (π/4). (ft .d/fb) ft .d/4fb (π/4). (ft .d3/fb) π ft .d²/fb (π/4). (ft .d/fb) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the depth of actual neutral axis of a doubly reinforced beam Is greater than the depth of critical neutral axis, the concrete attains its maximum stress earlier Is less than the depth of critical neutral axis, the steel in the tensile zone attains its maximum stress earlier All listed here Is equal to the depth of critical neutral axis; the concrete and steel attain their maximum stresses simultaneously Is greater than the depth of critical neutral axis, the concrete attains its maximum stress earlier Is less than the depth of critical neutral axis, the steel in the tensile zone attains its maximum stress earlier All listed here Is equal to the depth of critical neutral axis; the concrete and steel attain their maximum stresses simultaneously ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If l₁ and l₂ are the lengths of long and short spans of a two way slab simply supported on four edges and carrying a load w per unit area, the ratio of the loads split into w₁ and w₂ acting on strips parallel to l₂ and l₁ is w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ w₁/w₂ = l₂/l₁ w₁/w₂ = (l₂/l₁)² w₁/w₂ = (l₂/l₁)³ w₁/w₂ = (l₂/l₁)⁴ ANSWER DOWNLOAD EXAMIANS APP
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