Machine Design A circular shaft can transmit a torque of 5 kN-m. If the torque is reduced to 4 kN-m, then the maximum value of bending moment that can be applied to the shaft is 4 kN-m 3 kN-m 1 kN-m 2 kN-m 4 kN-m 3 kN-m 1 kN-m 2 kN-m ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the length of the journal is equal to the diameter of the journal, then the bearing is said to be a Long bearing Medium bearing Square bearing Short bearing Long bearing Medium bearing Square bearing Short bearing ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the belt is transmitting maximum power, the belt speed should be(Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N)) √(Pmax / 2m) √(3m /Pmax) √(Pmax / 3m) √(Pmax / m) √(Pmax / 2m) √(3m /Pmax) √(Pmax / 3m) √(Pmax / m) ANSWER DOWNLOAD EXAMIANS APP
Machine Design A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is 2050 N-m 2000 N-m 2136 N-m 2100 N-m 2050 N-m 2000 N-m 2136 N-m 2100 N-m ANSWER DOWNLOAD EXAMIANS APP
Machine Design The strength of the unriveted plate (P) per pitch length is equal to p.t.σt p.d.σt (p - d) t.σt (p - d) σt p.t.σt p.d.σt (p - d) t.σt (p - d) σt ANSWER DOWNLOAD EXAMIANS APP
Machine Design In the levers of first type, the mechanical advantage is ________ one. Less than Equal to More than None of these Less than Equal to More than None of these ANSWER DOWNLOAD EXAMIANS APP
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