Machine Design Endurance limit or fatigue limit is the maximum stress that a member can withstand for an infinite number of load applications without failure when subjected to Dynamic loading Completely reversed loading Combined static and dynamic loading Static loading Dynamic loading Completely reversed loading Combined static and dynamic loading Static loading ANSWER DOWNLOAD EXAMIANS APP
Machine Design Resilience of a material is important, when it is subjected to Combined loading Shock loading Fatigue Thermal stresses Combined loading Shock loading Fatigue Thermal stresses ANSWER DOWNLOAD EXAMIANS APP
Machine Design For longitudinal joint in boilers, the type of joint used is Butt joint with double cover plate Butt joint with single cover plate Lap joint with one ring overlapping the other Any one of the above Butt joint with double cover plate Butt joint with single cover plate Lap joint with one ring overlapping the other Any one of the above ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a butt welded joint, the size of weld is __________ the throat of weld. 2 times Double 0.5 times Equal to 2 times Double 0.5 times Equal to ANSWER DOWNLOAD EXAMIANS APP
Machine Design A compound belt drive is used when None of these Shafts are arranged parallel and rotate in the same directions Shafts are arranged at right angles and rotate in one definite direction Shafts are arranged parallel and rotate in the opposite directions None of these Shafts are arranged parallel and rotate in the same directions Shafts are arranged at right angles and rotate in one definite direction Shafts are arranged parallel and rotate in the opposite directions ANSWER DOWNLOAD EXAMIANS APP
Machine Design In a band and block brake, the ratio of tensions on the tight and slack sides of band is given by (where μ = Coefficient of friction between the blocks and the drum, θ = Semi-angle of each block subtending at the centre of drum, and n = Number of blocks) T₁/T₂ = μθ × n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = (μθ)n T₁/T₂ = μθ × n T₁/T₂ = [(1 - μ tanθ)/ (1 + μ tanθ)]n T₁/T₂ = [(1 + μ tanθ)/ (1 - μ tanθ)]n T₁/T₂ = (μθ)n ANSWER DOWNLOAD EXAMIANS APP
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