Theory of Machine With usual notations for different parameters involved, the maximum fluctuations of energy for a flywheel is given by 2ECS 2E²CS 2ECS² EC S/2 2ECS 2E²CS 2ECS² EC S/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The velocity of piston in a reciprocating steam engine is given by (where ω = Angular velocity of crank, r = Radius of crank pin circle, θ = Angle turned by crank from inner dead center, and n = Ratio of length of connecting rod to the radius of crank) ω²r [sin θ + (sin 2θ/n)] ωr [cos θ + (cos 2θ/n)] ωr [sin θ + (sin 2θ/n)] ω²r [cos θ + (cos 2θ/n)] ω²r [sin θ + (sin 2θ/n)] ωr [cos θ + (cos 2θ/n)] ωr [sin θ + (sin 2θ/n)] ω²r [cos θ + (cos 2θ/n)] ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Length of arc of contact is given by Arc of approach × Arc of recess Arc of approach / Arc of recess Arc of approach + Arc of recess Arc of approach - Arc of recess Arc of approach × Arc of recess Arc of approach / Arc of recess Arc of approach + Arc of recess Arc of approach - Arc of recess ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The velocity of any point in mechanism relative to any other point on the mechanism on velocity polygon is represented by the line Not possible to determine with these data Joining the corresponding points Perpendicular to line as per (A) At 45° to line as per (A) Not possible to determine with these data Joining the corresponding points Perpendicular to line as per (A) At 45° to line as per (A) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a radial cam, the follower moves In a direction perpendicular to the cam axis In a direction parallel to the cam axis In any direction irrespective of the cam axis Along the cam axis In a direction perpendicular to the cam axis In a direction parallel to the cam axis In any direction irrespective of the cam axis Along the cam axis ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In a reciprocating steam engine, when the crank has turned from inner dead centre through an angle θ, the angular velocity of the connecting rod is given by ω cosθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ω cosθ/(n² - sin²θ)1/2 ω cosθ/(n² - cos²θ)1/2 ω sinθ/(n² - sin²θ)1/2 ω sinθ/(n² - cos²θ)1/2 ANSWER DOWNLOAD EXAMIANS APP