Theory of Machine The relation between number of pairs (p) forming a kinematic chain and the number of links (l) is l = 2p - 2 l = 2p - 3 l = 2p - 5 l = 2p - 4 l = 2p - 2 l = 2p - 3 l = 2p - 5 l = 2p - 4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine An involute pinion and gear are in mesh. If both have the same size of addendum, then there will be an interference between the Tip of the gear tooth and flank of pinion Flanks of both gear and pinion Tip of the pinion and flank of gear Tip of both gear and pinion Tip of the gear tooth and flank of pinion Flanks of both gear and pinion Tip of the pinion and flank of gear Tip of both gear and pinion ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Angular acceleration of a link can be determined by dividing the All of these Centripetal component of acceleration with length of link Resultant acceleration with length of link Tangential component of acceleration with length of link All of these Centripetal component of acceleration with length of link Resultant acceleration with length of link Tangential component of acceleration with length of link ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine For S.H.M. cam, the acceleration of the follower at the ends of the stroke and aimed stroke respectively, is Zero and maximum Minimum and maximum Zero and minimum Maximum and zero Zero and maximum Minimum and maximum Zero and minimum Maximum and zero ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine A friction circle is a circle drawn when a journal rotates in a bearing. Its radius depends upon the coefficient of friction and the Angular velocity of journal Magnitude of the forces on journal Clearance between journal and bearing Radius of journal Angular velocity of journal Magnitude of the forces on journal Clearance between journal and bearing Radius of journal ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The ratio of height of Porter governor (when length of arms and links are equal) to the height of Watt's governor is (where m = Mass of the ball, and M = Mass on the sleeve) M/(m + M) (m + M)/m m/(m + M) (m + M)/M M/(m + M) (m + M)/m m/(m + M) (m + M)/M ANSWER DOWNLOAD EXAMIANS APP
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