MGVCL Exam Paper (30-07-2021 Shift 1) Which of the following is the layer of a computer system between the hardware and the user program? None of these Operating System System Environment Application Software None of these Operating System System Environment Application Software ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The term NEFT (in banking), is an abbreviation of ___ National Electronic Funds Transfer National Electronics Financial Transaction Net Electronics Financial Transfer Net Electronics Funds Transfer National Electronic Funds Transfer National Electronics Financial Transaction Net Electronics Financial Transfer Net Electronics Funds Transfer ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) In the following question, one part of the sentence may have an error. Find out which part of the sentence has an error and select the option corresponding to it. If the sentence contains no error, Select "No error'' option. (Avoid punctuation errors)(A) Bubin together with / (B) her parents are coming / (C) to attend the party. / (D) NO ERROR A B D C A B D C ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) At what range of wind speed is the electricity from the wind turbine is generated? 30-35 mph 450 – 650 mph 250 – 450 mph 100 – 125 mph 30-35 mph 450 – 650 mph 250 – 450 mph 100 – 125 mph ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For small turbine starts generating power 12.6 kph (3.5 m/s) is the typical cut-in speed.At 36–54 kph (10–15 m/s) produces maximum generation power.At 90 kph (25 m/s) maximum, the turbine is stopped or braked.
MGVCL Exam Paper (30-07-2021 Shift 1) A ___ is a device that forwards packets between networks by processing the routing information included in the packet. Firewall Router all the mentioned above Bridge Firewall Router all the mentioned above Bridge ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) Determine maximum permissible load which a 15 MVA, ONAN cooled transformer to IS : 2026 can take for 6 hr, if the initial load on it was 12 MVA. The weighted ambient temperature is 20˚C. Assume the permissible load kVA as a fraction of rated kVA is 1.25. 9.6 MVA 15 MVA 12 MVA 18.75 MVA 9.6 MVA 15 MVA 12 MVA 18.75 MVA ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Maximum permissible load = Rated MVA rating*fraction of rated kVAMaximum permissible load = 15*1.25Maximum permissible load = 18.75 MVA
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