MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is not a Font style in Microsoft Word? Italic Superscript Regular Bold Italic Superscript Regular Bold ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) સોહેલ ખાન : મલાયકા અરોર :: સૈફ અલી ખાન : ?? માધુરી દિક્ષિત અમૃતા સિંહ પરવીન બાબી કિરણ ખેર માધુરી દિક્ષિત અમૃતા સિંહ પરવીન બાબી કિરણ ખેર ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Tree Topology Paper size Web layout Page Orientation Font style Paper size Web layout Page Orientation Font style ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Which one of the following statement is TRUE? The current carrying capacity of cables in DC is less than that in AC. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. In the cables, sheaths are used to provide enough strength. The current carrying capacity of cables in DC is less than that in AC. Underground cables are laid at sufficient depth to avoid being unearthed easily due to removal of soil. In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors. In the cables, sheaths are used to provide enough strength. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the cables, the location of fault is usually found out by comparing the capacitances of insulated conductors.
MGVCL Exam Paper (30-07-2021 Shift 2) The Great Barrier Reef is located in which country? Australia Germany India Canada Australia Germany India Canada ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A delta-connected balanced three-phase load is supplied from a three-phase, 400 V supply. The line current is 20 A and the power taken by the load is 10 kW. Find the power factor. 0.82 0.62 0.52 0.72 0.82 0.62 0.52 0.72 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP P = 10 kWVL = 400 VIL = 20 A3- phse power, P = √3*VL*IL*cosφcosφ = 10*1000/(√3*400*20)= 0.7216
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