MGVCL Exam Paper (30-07-2021 Shift 2) Which of the following is not a Font style in Microsoft Word? Bold Superscript Italic Regular Bold Superscript Italic Regular ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) In circuit breaker, the term MCCB stands for miniature case circuit breaker moulded case circuit breaker miniature compact circuit breaker modern closed circuit breaker miniature case circuit breaker moulded case circuit breaker miniature compact circuit breaker modern closed circuit breaker ANSWER EXPLANATION DOWNLOAD EXAMIANS APP MCCB stands for Moulded Case Circuit Breaker.MCB stands for Miniature Circuit Breaker.ELCB stands for Earth Leakage Circuit BreakerRCCB stands for Residual Current Circuit Breaker.
MGVCL Exam Paper (30-07-2021 Shift 2) Choose the best option from the given alternatives which can be substituted for the given word/sentence.A person who kills somebody especially for political reasons Assassin Alien Pauper Stoic Assassin Alien Pauper Stoic ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) Rearrange the following to form a meaningful sentence and find the most logical order from the given options.P: dancers make the companyQ: and they do not haveR: a big team of professionalS: a ‘guru shishya’ hierarchy PQSR RPSQ RPQS PQRS PQSR RPSQ RPQS PQRS ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) સોહેલ ખાન : મલાયકા અરોર :: સૈફ અલી ખાન : ?? કિરણ ખેર પરવીન બાબી અમૃતા સિંહ માધુરી દિક્ષિત કિરણ ખેર પરવીન બાબી અમૃતા સિંહ માધુરી દિક્ષિત ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 2) A 3-phase motor load has a p.f. of 0.397 lagging. The two wattmeter method used to measure power show the input as 30 kW. Find the reading on each wattmeter. W1 = 5 kW and W2 = 25 kW W1 = -10 kW and W2 = 40 kW W1 = -5 kW and W2 = 35 kW W1 = 10 kW and W2 = 20 kW W1 = 5 kW and W2 = 25 kW W1 = -10 kW and W2 = 40 kW W1 = -5 kW and W2 = 35 kW W1 = 10 kW and W2 = 20 kW ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,Cosφ = 0.397P = 30 kW = √3*V_L*I_L*cosφV_L*I_L = 30kW/(√3*0.397) = 43628.48 VAReadings of wattmeter W1 = V_L*I_L*cos(30+φ)Readings of wattmeter W2 = V_L*I_L*cos(30-φ)
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